How to solve (-1)^(2)-5(-1)-6

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (-1)^(2)-5(-1)-6 | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$${ -1 }^{ 2 } -5(-1)-6$$

Evaluate

$0$

Solution Steps

Calculate $-1$ to the power of $2$ and get $1$.

$$1-5\left(-1\right)-6$$

Multiply $5$ and $-1$ to get $-5$.

$$1-\left(-5\right)-6$$

The opposite of $-5$ is $5$.

$$1+5-6$$

Add $1$ and $5$ to get $6$.

$$6-6$$

Subtract $6$ from $6$ to get $0$.

$$0$$

Show Solution

Factor

$0$

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