How to solve (-1)^(2)+2(-1)+10

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (-1)^(2)+2(-1)+10 | Equatix

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3(r+2s)=2t-4

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Question

$${ -1 }^{ 2 } +2(-1)+10$$

Evaluate

$9$

Solution Steps

Calculate $-1$ to the power of $2$ and get $1$.

$$1+2\left(-1\right)+10$$

Multiply $2$ and $-1$ to get $-2$.

$$1-2+10$$

Subtract $2$ from $1$ to get $-1$.

$$-1+10$$

Add $-1$ and $10$ to get $9$.

$$9$$

Show Solution

Factor

$3^{2}$

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