How to solve (-1)^(2)+7(-1)+10

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (-1)^(2)+7(-1)+10 | Equatix

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3(r+2s)=2t-4

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Question

$${ -1 }^{ 2 } +7(-1)+10$$

Evaluate

$4$

Solution Steps

Calculate $-1$ to the power of $2$ and get $1$.

$$1+7\left(-1\right)+10$$

Multiply $7$ and $-1$ to get $-7$.

$$1-7+10$$

Subtract $7$ from $1$ to get $-6$.

$$-6+10$$

Add $-6$ and $10$ to get $4$.

$$4$$

Show Solution

Factor

$2^{2}$

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