$$\{-10-[12+(-3)^{2}]+3^{3}\}\div(-3)$$
$\frac{4}{3}\approx 1.333333333$
$$\frac{-10-\left(12+9\right)+3^{3}}{-3}$$
$$\frac{-10-21+3^{3}}{-3}$$
$$\frac{-31+3^{3}}{-3}$$
$$\frac{-31+27}{-3}$$
$$\frac{-4}{-3}$$
$$\frac{4}{3}$$
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$\frac{2 ^ {2}}{3} = 1\frac{1}{3} = 1.3333333333333333$
