$${ x }^{ 2 } 5+2 \times 4$$
$10x$
$$\frac{\mathrm{d}}{\mathrm{d}x}(x^{2}\times 5+8)$$
$$2\times 5x^{2-1}$$
$$10x^{2-1}$$
$$10x^{1}$$
$$10x$$
Show Solution
Hide Solution
$5x^{2}+8$
$$x^{2}\times 5+8$$