How to solve (x)^(2)-2x+3,x=1

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (x)^(2)-2x+3,x=1 | Equatix

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3(r+2s)=2t-4

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Question

$${ x }^{ 2 } -2x+3,x=1$$

Solve for x, y

$y=2$

Solution Steps

Consider the second equation. Insert the known values of variables into the equation.

$$y=1^{2}-2+3$$

Calculate $1$ to the power of $2$ and get $1$.

$$y=1-2+3$$

Subtract $2$ from $1$ to get $-1$.

$$y=-1+3$$

Add $-1$ and $3$ to get $2$.

$$y=2$$

The system is now solved.

$$x=1$$ $$y=2$$

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Question

Solve for x, y

Solution Steps