How to solve (x)^(2)-2x+3,x=10

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (x)^(2)-2x+3,x=10 | Equatix

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Question

$${ x }^{ 2 } -2x+3,x=10$$

Solve for x, y

$y=83$

Solution Steps

Consider the second equation. Insert the known values of variables into the equation.

$$y=10^{2}-2\times 10+3$$

Calculate $10$ to the power of $2$ and get $100$.

$$y=100-2\times 10+3$$

Multiply $-2$ and $10$ to get $-20$.

$$y=100-20+3$$

Subtract $20$ from $100$ to get $80$.

$$y=80+3$$

Add $80$ and $3$ to get $83$.

$$y=83$$

The system is now solved.

$$x=10$$ $$y=83$$

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Solve for x, y

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