Question

$${ x }^{ 2 } -4x=8$$

Answer

x=2*(1+sqrt(3)),2*(1-sqrt(3))

Solution


Move all terms to one side.
\[{x}^{2}-4x-8=0\]
Use the Quadratic Formula.
\[x=\frac{4+4\sqrt{3}}{2},\frac{4-4\sqrt{3}}{2}\]
Simplify solutions.
\[x=2(1+\sqrt{3}),2(1-\sqrt{3})\]

Decimal Form: 5.464102, -1.464102