$${ x }^{ 2 } -5x+6/ { x }^{ 2 } -9-x-3/x+4$$
$x^{2}-6x-5-\frac{3}{x}+\frac{6}{x^{2}}$
$$x^{2}-6x+\frac{6}{x^{2}}-9-\frac{3}{x}+4$$
$$x^{2}-6x+\frac{6}{x^{2}}-5-\frac{3}{x}$$
$$\frac{\left(x^{2}-6x-5\right)x^{2}}{x^{2}}+\frac{6}{x^{2}}-\frac{3}{x}$$
$$\frac{\left(x^{2}-6x-5\right)x^{2}+6}{x^{2}}-\frac{3}{x}$$
$$\frac{x^{4}-6x^{3}-5x^{2}+6}{x^{2}}-\frac{3}{x}$$
$$\frac{x^{4}-6x^{3}-5x^{2}+6}{x^{2}}-\frac{3x}{x^{2}}$$
$$\frac{x^{4}-6x^{3}-5x^{2}+6-3x}{x^{2}}$$
Show Solution
Hide Solution
$\frac{x^{4}-6x^{3}-5x^{2}-3x+6}{x^{2}}$