$${ x }^{ 2 } - \frac{ 1 }{ 4 }$$
$\frac{\left(2x-1\right)\left(2x+1\right)}{4}$
$$\frac{4x^{2}-1}{4}$$
$$\left(2x-1\right)\left(2x+1\right)$$
$$\frac{\left(2x-1\right)\left(2x+1\right)}{4}$$
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$x^{2}-\frac{1}{4}$