How to solve (X)^(2)+5x+4=0

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (X)^(2)+5x+4=0 | Equatix

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3(r+2s)=2t-4

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3(r+2s)=2t-4

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Question

$${ X }^{ 2 } +5x+4=0$$

Solve for x

$x=\frac{-X^{2}-4}{5}$

Steps for Solving Linear Equation

Subtract $X^{2}$ from both sides. Anything subtracted from zero gives its negation.

$$5x+4=-X^{2}$$

Subtract $4$ from both sides.

$$5x=-X^{2}-4$$

Divide both sides by $5$.

$$\frac{5x}{5}=\frac{-X^{2}-4}{5}$$

Dividing by $5$ undoes the multiplication by $5$.

$$x=\frac{-X^{2}-4}{5}$$

Show Solution

Solve for X (complex solution)

$X=-\sqrt{-5x-4}$
$X=\sqrt{-5x-4}$

Solve for X

$X=\sqrt{-5x-4}$
$X=-\sqrt{-5x-4}\text{, }x\leq -\frac{4}{5}$

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