Question

$${ x }^{ 2 } +y(4x+y-1)+2=0$$

Solve for x (complex solution)

$x=\sqrt{\left(3y-2\right)\left(y+1\right)}-2y$
$x=-\sqrt{\left(3y-2\right)\left(y+1\right)}-2y$

Solve for y (complex solution)

$y=\frac{\sqrt{12x^{2}-8x-7}}{2}-2x+\frac{1}{2}$
$y=-\frac{\sqrt{12x^{2}-8x-7}}{2}-2x+\frac{1}{2}$

Solve for x

$x=\sqrt{\left(3y-2\right)\left(y+1\right)}-2y$
$x=-\sqrt{\left(3y-2\right)\left(y+1\right)}-2y\text{, }y\leq -1\text{ or }y\geq \frac{2}{3}$

Solve for y

$y=\frac{\sqrt{12x^{2}-8x-7}}{2}-2x+\frac{1}{2}$
$y=-\frac{\sqrt{12x^{2}-8x-7}}{2}-2x+\frac{1}{2}\text{, }x\leq -\frac{1}{2}\text{ or }x\geq \frac{7}{6}$