$${ x }^{ 3 } -2xy+3 { x }^{ 2 } y-6 { y }^{ 2 }$$
Factor
$\left(x+3y\right)\left(x^{2}-2y\right)$
Solution Steps
Do the grouping $x^{3}-2xy+3x^{2}y-6y^{2}=\left(x^{3}-2xy\right)+\left(3x^{2}y-6y^{2}\right)$, and factor out $x$ in the first and $3y$ in the second group.