$${ x }^{ 3 } +2 { x }^{ 2 } y-2xy-4 { y }^{ 2 }$$
Factor
$\left(x+2y\right)\left(x^{2}-2y\right)$
Solution Steps
Do the grouping $x^{3}+2x^{2}y-2xy-4y^{2}=\left(x^{3}+2x^{2}y\right)+\left(-2xy-4y^{2}\right)$, and factor out $x^{2}$ in the first and $-2y$ in the second group.
$$x^{2}\left(x+2y\right)-2y\left(x+2y\right)$$
Factor out common term $x+2y$ by using distributive property.
