How to solve (x)^(6)-4x-32

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (x)^(6)-4x-32 | Equatix

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Question

$${ x }^{ 6 } -4x-32$$

Differentiate w.r.t. x

$6x^{5}-4$

Steps Using Derivative Rule for Sum

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is $0$. The derivative of $ax^{n}$ is $nax^{n-1}$.

$$6x^{6-1}-4x^{1-1}$$

Subtract $1$ from $6$.

$$6x^{5}-4x^{1-1}$$

Subtract $1$ from $1$.

$$6x^{5}-4x^{0}$$

For any term $t$ except $0$, $t^{0}=1$.

$$6x^{5}-4$$

Show Solution

Evaluate

$x^{6}-4x-32$