Consider $y^{2}-576$. Rewrite $y^{2}-576$ as $y^{2}-24^{2}$. The difference of squares can be factored using the rule: $a^{2}-b^{2}=\left(a-b\right)\left(a+b\right)$.
$$\left(y-24\right)\left(y+24\right)=0$$
To find equation solutions, solve $y-24=0$ and $y+24=0$.
$$y=24$$ $$y=-24$$
Steps by Finding Square Root
Take the square root of both sides of the equation.
$$y=24$$ $$y=-24$$
Steps Using the Quadratic Formula
Subtract $576$ from both sides.
$$y^{2}-576=0$$
This equation is in standard form: $ax^{2}+bx+c=0$. Substitute $1$ for $a$, $0$ for $b$, and $-576$ for $c$ in the quadratic formula, $\frac{-b±\sqrt{b^{2}-4ac}}{2a}$.
$$y=\frac{0±\sqrt{0^{2}-4\left(-576\right)}}{2}$$
Square $0$.
$$y=\frac{0±\sqrt{-4\left(-576\right)}}{2}$$
Multiply $-4$ times $-576$.
$$y=\frac{0±\sqrt{2304}}{2}$$
Take the square root of $2304$.
$$y=\frac{0±48}{2}$$
Now solve the equation $y=\frac{0±48}{2}$ when $±$ is plus. Divide $48$ by $2$.
$$y=24$$
Now solve the equation $y=\frac{0±48}{2}$ when $±$ is minus. Divide $-48$ by $2$.
