Question

$${ y }^{ 2 } +y(4+(-3))+4 \times (-3)$$

Answer

$$y^2+y-12$$

Solution


Remove parentheses.
\[{y}^{2}+y(4-3)+4\times -3\]
Simplify  \(4-3\)  to  \(1\).
\[{y}^{2}+y\times 1+4\times -3\]
Simplify  \(y\times 1\)  to  \(y\).
\[{y}^{2}+y+4\times -3\]
Simplify  \(4\times -3\)  to  \(-12\).
\[{y}^{2}+y-12\]