Solve D=| 2 3 - 1 2 :3|= | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$D=|\frac{2}{3}-\frac{1}{2}:3|=$$

Solve for D

$D=\frac{1}{2}=0.5$

Steps for Solving Linear Equation

Express $\frac{\frac{1}{2}}{3}$ as a single fraction.

$$D=|\frac{2}{3}-\frac{1}{2\times 3}|$$

Multiply $2$ and $3$ to get $6$.

$$D=|\frac{2}{3}-\frac{1}{6}|$$

Least common multiple of $3$ and $6$ is $6$. Convert $\frac{2}{3}$ and $\frac{1}{6}$ to fractions with denominator $6$.

$$D=|\frac{4}{6}-\frac{1}{6}|$$

Since $\frac{4}{6}$ and $\frac{1}{6}$ have the same denominator, subtract them by subtracting their numerators.

$$D=|\frac{4-1}{6}|$$

Subtract $1$ from $4$ to get $3$.

$$D=|\frac{3}{6}|$$

Reduce the fraction $\frac{3}{6}$ to lowest terms by extracting and canceling out $3$.

$$D=|\frac{1}{2}|$$

The absolute value of a real number $a$ is $a$ when $a\geq 0$, or $-a$ when $a<0$. The absolute value of $\frac{1}{2}$ is $\frac{1}{2}$.

$$D=\frac{1}{2}$$

Assign D

$D≔\frac{1}{2}$