Question

$$D=\dot{x}^{3}+27+(3x-2)(x+3)+(x^{2}-9)$$

Answer

$$D=d*o*t*x^3+18+(3*x-2)*(x+3)+x^2$$

Solution


Remove parentheses.
\[D=dot{x}^{3}+27+(3x-2)(x+3)+{x}^{2}-9\]
Simplify  \(dot{x}^{3}+27+(3x-2)(x+3)+{x}^{2}-9\)  to  \(dot{x}^{3}+18+(3x-2)(x+3)+{x}^{2}\).
\[D=dot{x}^{3}+18+(3x-2)(x+3)+{x}^{2}\]