How to solve D = 17/10 - 11/27

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve D = 17/10 - 11/27 | Equatix

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$$D=\frac{17}{10}-\frac{11}{27}$$

$D = \frac{349}{270} = 1\frac{79}{270} \approx 1.292592593$

Least common multiple of $10$ and $27$ is $270$. Convert $\frac{17}{10}$ and $\frac{11}{27}$ to fractions with denominator $270$.

$$D=\frac{459}{270}-\frac{110}{270}$$

Since $\frac{459}{270}$ and $\frac{110}{270}$ have the same denominator, subtract them by subtracting their numerators.

$$D=\frac{459-110}{270}$$

Subtract $110$ from $459$ to get $349$.

$$D=\frac{349}{270}$$

$D≔\frac{349}{270}$