Remove parentheses.
\[Threepo\imath ntsareD3,3,R(1,2)andS(7,5)Showthat\]
Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[Th{r}^{2}{e}^{2}po\imath ntsaeD3,3,R(1,2)andS(7,5)Showthat\]
Regroup terms.
\[Th{e}^{2}eD3\imath {r}^{2}pontsa,3,R(1,2)andS(7,5)Showthat\]
Simplify \(R(1,2)andS(7,5)Showthat\) to \(R\times 1,2andS(7,5)Showthat\).
\[Th{e}^{2}eD3\imath {r}^{2}pontsa,3,R\times 1,2andS(7,5)Showthat\]
Simplify \(R\times 1\) to \(R\).
\[Th{e}^{2}eD3\imath {r}^{2}pontsa,3,R,2andS(7,5)Showthat\]
Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[Th{e}^{2}eD3\imath {r}^{2}pontsa,3,R,2{a}^{2}ndS(7,5)Show{t}^{2}h\]
Regroup terms.
\[Th{e}^{2}eD3\imath {r}^{2}pontsa,3,R,2dS(7,5)Sh{a}^{2}now{t}^{2}h\]
Th*e^2*eD3*IM*r^2*p*o*n*t*s*a,3,R,2*dS(7,5)*Sh*a^2*n*o*w*t^2*h
