Question

$$\displaystyle\frac{d}{d \left(3x \right) } \left( \sin h3x \right)$$

Answer

$$3*IM*d*f^2*x,3*x*sin(h)$$

Solution


Regroup terms.
\[d\imath ff(3x,3x\sin{h})\]
Simplify.
\[d\imath ff\times 3x,3x\sin{h}\]
Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[d\imath {f}^{2}\times 3x,3x\sin{h}\]
Regroup terms.
\[3\imath d{f}^{2}x,3x\sin{h}\]