Question

$$\displaystyle\frac{d}{d \left(xx \right) } \left(6x+8 \times 3 \right)$$

Answer

$$IM*d*f^2*(x^2,6*x+24)$$

Solution


Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[d\imath ff({x}^{2},6x+8\times 3)\]
Simplify  \(8\times 3\)  to  \(24\).
\[d\imath ff({x}^{2},6x+24)\]
Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[d\imath {f}^{2}({x}^{2},6x+24)\]
Regroup terms.
\[\imath d{f}^{2}({x}^{2},6x+24)\]