Question

$$\displaystyle\frac{d}{d \left(xxx \right) } \left(3 \sin x \cos 2x \right)$$

Answer

$$IM*d*f^2*x^3,3*sin(x)*cos(2*x)$$

Solution


Simplify  \(xxx\)  to  \({x}^{3}\).
\[d\imath ff({x}^{3},3\sin{x}\cos{2x})\]
Simplify.
\[d\imath ff{x}^{3},3\sin{x}\cos{2x}\]
Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[d\imath {f}^{2}{x}^{3},3\sin{x}\cos{2x}\]
Regroup terms.
\[\imath d{f}^{2}{x}^{3},3\sin{x}\cos{2x}\]