$$\displaystyle\int{ \frac{ 1 }{ { \left( { e }^{ x } + { e }^{ -x } \right) }^{ 2 } } }d x$$
$-\frac{1}{2\left(e^{2x}+1\right)}+С$
$\frac{e^{2x}}{\left(e^{2x}+1\right)^{2}}$
