Example

3(r+2s)=2t-4
a⋅(b-2)=3b
3(r+2s)=2t-4
a⋅(b-2)=3b

Question

$$\displaystyle\int{ \frac{ 1 }{ \sqrt{ 16-(3x+4) { \left( \right) }^{ 2 } } } }d x$$

Answer

$$1/sqrt(16-(3*x+4)*()^2)*d*x$$

Solution


Use this rule: \(\int a \, dx=ax+C\).
\[\frac{1}{\sqrt{16-(3x+4){()}^{2}}}dx\]
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