$$\displaystyle\int{ \frac{ 4 { x }^{ 3 } +5 { x }^{ 2 } +2 }{ { x }^{ 3 } + { x }^{ 2 } +1 } }d x$$
$\int \frac{4x^{3}+5x^{2}+2}{x^{3}+x^{2}+1}\mathrm{d}x$
$\frac{4x^{3}+5x^{2}+2}{x^{3}+x^{2}+1}$
