$$\displaystyle\int{ \frac{ { \sec }^{ 2 } { \cot }^{ -1 } x }{ 1+ { x }^{ 2 } } }d x$$
$\int \frac{1}{\left(x-i\right)\left(x+i\right)\left(\cos(x)\right)^{2}}\mathrm{d}x$
