Question

$$\displaystyle\int{ \frac{ x+1 }{ { \left(x-1 \right) }^{ 2 } ( { x }^{ 2 } +1) } }d x$$

Answer

$$(x^2*d*(x/2+1))/((x-1)^2*(x^2+1))$$

Solution


Use Power Rule: \(\int {x}^{n} \, dx=\frac{{x}^{n+1}}{n+1}+C\).
\[\frac{{x}^{2}d(\frac{x}{2}+1)}{{(x-1)}^{2}({x}^{2}+1)}\]