$$\displaystyle\int_{ -1 }^{ 1 } 1 d x - \displaystyle\int_{ -1 }^{ 1 } \frac{ \cos 2mx }{ 2m } d x$$
$\frac{-\frac{\sin(2m)}{m^{2}}+4}{2}$
$\frac{-m\cos(2m)+\sin(2m)}{m^{3}}$
