Question

$$\cdot \cos e c e t + \cot \theta \gt p \quad }$$

Answer

$$s=1/(Co*e^4*t^2*h^2*n*p*r*o*v)$$

Solution


Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[Cos{e}^{4}{t}^{2}{h}^{2}nprov={p}^{2}-1\times {p}^{2}+1\]
Regroup terms.
\[Co{e}^{4}s{t}^{2}{h}^{2}nprov={p}^{2}-1\times {p}^{2}+1\]
Simplify  \(1\times {p}^{2}\)  to  \({p}^{2}\).
\[Co{e}^{4}s{t}^{2}{h}^{2}nprov={p}^{2}-{p}^{2}+1\]
Simplify  \({p}^{2}-{p}^{2}+1\)  to  \(1\).
\[Co{e}^{4}s{t}^{2}{h}^{2}nprov=1\]
Divide both sides by \(Co\).
\[{e}^{4}s{t}^{2}{h}^{2}nprov=\frac{1}{Co}\]
Divide both sides by \({e}^{4}\).
\[s{t}^{2}{h}^{2}nprov=\frac{\frac{1}{Co}}{{e}^{4}}\]
Simplify  \(\frac{\frac{1}{Co}}{{e}^{4}}\)  to  \(\frac{1}{Co{e}^{4}}\).
\[s{t}^{2}{h}^{2}nprov=\frac{1}{Co{e}^{4}}\]
Divide both sides by \({t}^{2}\).
\[s{h}^{2}nprov=\frac{\frac{1}{Co{e}^{4}}}{{t}^{2}}\]
Simplify  \(\frac{\frac{1}{Co{e}^{4}}}{{t}^{2}}\)  to  \(\frac{1}{Co{e}^{4}{t}^{2}}\).
\[s{h}^{2}nprov=\frac{1}{Co{e}^{4}{t}^{2}}\]
Divide both sides by \({h}^{2}\).
\[snprov=\frac{\frac{1}{Co{e}^{4}{t}^{2}}}{{h}^{2}}\]
Simplify  \(\frac{\frac{1}{Co{e}^{4}{t}^{2}}}{{h}^{2}}\)  to  \(\frac{1}{Co{e}^{4}{t}^{2}{h}^{2}}\).
\[snprov=\frac{1}{Co{e}^{4}{t}^{2}{h}^{2}}\]
Divide both sides by \(n\).
\[sprov=\frac{\frac{1}{Co{e}^{4}{t}^{2}{h}^{2}}}{n}\]
Simplify  \(\frac{\frac{1}{Co{e}^{4}{t}^{2}{h}^{2}}}{n}\)  to  \(\frac{1}{Co{e}^{4}{t}^{2}{h}^{2}n}\).
\[sprov=\frac{1}{Co{e}^{4}{t}^{2}{h}^{2}n}\]
Divide both sides by \(p\).
\[srov=\frac{\frac{1}{Co{e}^{4}{t}^{2}{h}^{2}n}}{p}\]
Simplify  \(\frac{\frac{1}{Co{e}^{4}{t}^{2}{h}^{2}n}}{p}\)  to  \(\frac{1}{Co{e}^{4}{t}^{2}{h}^{2}np}\).
\[srov=\frac{1}{Co{e}^{4}{t}^{2}{h}^{2}np}\]
Divide both sides by \(r\).
\[sov=\frac{\frac{1}{Co{e}^{4}{t}^{2}{h}^{2}np}}{r}\]
Simplify  \(\frac{\frac{1}{Co{e}^{4}{t}^{2}{h}^{2}np}}{r}\)  to  \(\frac{1}{Co{e}^{4}{t}^{2}{h}^{2}npr}\).
\[sov=\frac{1}{Co{e}^{4}{t}^{2}{h}^{2}npr}\]
Divide both sides by \(o\).
\[sv=\frac{\frac{1}{Co{e}^{4}{t}^{2}{h}^{2}npr}}{o}\]
Simplify  \(\frac{\frac{1}{Co{e}^{4}{t}^{2}{h}^{2}npr}}{o}\)  to  \(\frac{1}{Co{e}^{4}{t}^{2}{h}^{2}npro}\).
\[sv=\frac{1}{Co{e}^{4}{t}^{2}{h}^{2}npro}\]
Divide both sides by \(v\).
\[s=\frac{\frac{1}{Co{e}^{4}{t}^{2}{h}^{2}npro}}{v}\]
Simplify  \(\frac{\frac{1}{Co{e}^{4}{t}^{2}{h}^{2}npro}}{v}\)  to  \(\frac{1}{Co{e}^{4}{t}^{2}{h}^{2}nprov}\).
\[s=\frac{1}{Co{e}^{4}{t}^{2}{h}^{2}nprov}\]