$$\cdot\frac{7}{4}-\frac{13}{28}$$
$x = \frac{9}{7} = 1\frac{2}{7} = 1.2857142857142858$
$$\frac{49}{28}-\frac{13}{28}+x$$
$$\frac{49-13}{28}+x$$
$$\frac{36}{28}+x$$
$$\frac{9}{7}+x$$
Show Solution
Hide Solution
$\frac{7x+9}{7}$
$$\frac{36+28x}{28}$$
$$28x+36$$
$$4\left(7x+9\right)$$
$$\frac{7x+9}{7}$$
