Question

$$\cdot\int e^{-2x}(1-x)dx$$

Answer

$$(IM*n*t*x^2*d*(1-x))/e^2$$

Solution


Use Negative Power Rule: \({x}^{-a}=\frac{1}{{x}^{a}}\).
\[\imath nt\times \frac{1}{{e}^{2}}x(1-x)dx\]
Regroup terms.
\[ntxxd\imath \times \frac{1-x}{{e}^{2}}\]
Use this rule: \(\frac{a}{b} \times \frac{c}{d}=\frac{ac}{bd}\).
\[\frac{ntxxd\imath (1-x)}{{e}^{2}}\]
Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[\frac{nt{x}^{2}d\imath (1-x)}{{e}^{2}}\]
Regroup terms.
\[\frac{\imath nt{x}^{2}d(1-x)}{{e}^{2}}\]