Factor with quadratic formula.
In general, given \(a{x}^{2}+bx+c\), the factored form is:
\[a(x-\frac{-b+\sqrt{{b}^{2}-4ac}}{2a})(x-\frac{-b-\sqrt{{b}^{2}-4ac}}{2a})\]
In this case, \(a=6\), \(b=-5{y}^{2}\) and \(c=-6{y}^{4}\).
\[6(x-\frac{5{y}^{2}+\sqrt{{(-5{y}^{2})}^{2}-4\times 6\times -6{y}^{4}}}{2\times 6})(x-\frac{5{y}^{2}-\sqrt{{(-5{y}^{2})}^{2}-4\times 6\times -6{y}^{4}}}{2\times 6})\]
Simplify.
\[(2{x}^{2}-3{y}^{2})(3{x}^{2}+2{y}^{2})\]
Cancel \(3{x}^{2}+2{y}^{2}\).
