Question

$$E=\sqrt{2\sqrt{25}-6-\sqrt{9+\sqrt{49}}};$$

Answer

E=0

Solution


Since \(5\times 5=25\), the square root of \(25\) is \(5\).
\[E=\sqrt{2\times 5-6-\sqrt{9+\sqrt{49}}}\]
Since \(7\times 7=49\), the square root of \(49\) is \(7\).
\[E=\sqrt{2\times 5-6-\sqrt{9+7}}\]
Simplify  \(9+7\)  to  \(16\).
\[E=\sqrt{2\times 5-6-\sqrt{16}}\]
Since \(4\times 4=16\), the square root of \(16\) is \(4\).
\[E=\sqrt{2\times 5-6-4}\]
Simplify  \(2\times 5\)  to  \(10\).
\[E=\sqrt{10-6-4}\]
Simplify  \(10-6\)  to  \(4\).
\[E=\sqrt{4-4}\]
Simplify  \(4-4\)  to  \(0\).
\[E=\sqrt{0}\]
Simplify  \(\sqrt{0}\)  to  \(0\).
\[E=0\]