Example

3(r+2s)=2t-4
a⋅(b-2)=3b
3(r+2s)=2t-4
a⋅(b-2)=3b

Question

$$ECUASIONESDESEGUNDOGADO-2 { \times }^{ 2 } -5x+3=0$$

Answer

$$x=-(2*^3-ECUASIONESDESEGUNDOGADO-3)/5$$

Solution


Remove parentheses.
\[ECUASIONESDESEGUNDOGADO-2{}^{2}-5x+3=0\]
Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[ECUASIONESDESEGUNDOGADO-2{}^{3}-5x+3=0\]
Subtract \(ECUASIONESDESEGUNDOGADO\) from both sides.
\[-2{}^{3}-5x+3=-ECUASIONESDESEGUNDOGADO\]
Add \(2{}^{3}\) to both sides.
\[-5x+3=-ECUASIONESDESEGUNDOGADO+2{}^{3}\]
Regroup terms.
\[-5x+3=2{}^{3}-ECUASIONESDESEGUNDOGADO\]
Subtract \(3\) from both sides.
\[-5x=2{}^{3}-ECUASIONESDESEGUNDOGADO-3\]
Divide both sides by \(-5\).
\[x=-\frac{2{}^{3}-ECUASIONESDESEGUNDOGADO-3}{5}\]
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