Solve EFFectueA= 1 2 -1 2+ 3 3 +3 12 37 + 1 2 / 1 3- 1 2 - 4 7 4 7 + 3 10 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$EFFectueA=\frac{\frac{1}{2}\frac{-1}{2+\frac{3}{3}+3}}{\frac{12}{37}+\frac{1}{2}}\div\frac{\frac{1}{3-\frac{1}{2}}-\frac{4}{7}}{\frac{4}{7}+\frac{3}{10}}$$

Solve for A

$A=\frac{37}{72Ectu\left(eF\right)^{2}}$
$u\neq 0\text{ and }c\neq 0\text{ and }t\neq 0\text{ and }F\neq 0\text{ and }E\neq 0$

Steps for Solving Linear Equation

Multiply $F$ and $F$ to get $F^{2}$.

$$EF^{2}ectueA=\frac{\frac{\frac{1}{2}\times \frac{-1}{2+\frac{3}{3}+3}}{\frac{12}{37}+\frac{1}{2}}}{\frac{\frac{1}{3-\frac{1}{2}}-\frac{4}{7}}{\frac{4}{7}+\frac{3}{10}}}$$

Multiply $e$ and $e$ to get $e^{2}$.

$$EF^{2}e^{2}ctuA=\frac{\frac{\frac{1}{2}\times \frac{-1}{2+\frac{3}{3}+3}}{\frac{12}{37}+\frac{1}{2}}}{\frac{\frac{1}{3-\frac{1}{2}}-\frac{4}{7}}{\frac{4}{7}+\frac{3}{10}}}$$

Divide $\frac{\frac{1}{2}\times \frac{-1}{2+\frac{3}{3}+3}}{\frac{12}{37}+\frac{1}{2}}$ by $\frac{\frac{1}{3-\frac{1}{2}}-\frac{4}{7}}{\frac{4}{7}+\frac{3}{10}}$ by multiplying $\frac{\frac{1}{2}\times \frac{-1}{2+\frac{3}{3}+3}}{\frac{12}{37}+\frac{1}{2}}$ by the reciprocal of $\frac{\frac{1}{3-\frac{1}{2}}-\frac{4}{7}}{\frac{4}{7}+\frac{3}{10}}$.

$$EF^{2}e^{2}ctuA=\frac{\frac{1}{2}\times \frac{-1}{2+\frac{3}{3}+3}\left(\frac{4}{7}+\frac{3}{10}\right)}{\left(\frac{12}{37}+\frac{1}{2}\right)\left(\frac{1}{3-\frac{1}{2}}-\frac{4}{7}\right)}$$

Divide $3$ by $3$ to get $1$.

$$EF^{2}e^{2}ctuA=\frac{\frac{1}{2}\times \frac{-1}{2+1+3}\left(\frac{4}{7}+\frac{3}{10}\right)}{\left(\frac{12}{37}+\frac{1}{2}\right)\left(\frac{1}{3-\frac{1}{2}}-\frac{4}{7}\right)}$$

Add $2$ and $1$ to get $3$.

$$EF^{2}e^{2}ctuA=\frac{\frac{1}{2}\times \frac{-1}{3+3}\left(\frac{4}{7}+\frac{3}{10}\right)}{\left(\frac{12}{37}+\frac{1}{2}\right)\left(\frac{1}{3-\frac{1}{2}}-\frac{4}{7}\right)}$$

Add $3$ and $3$ to get $6$.

$$EF^{2}e^{2}ctuA=\frac{\frac{1}{2}\times \frac{-1}{6}\left(\frac{4}{7}+\frac{3}{10}\right)}{\left(\frac{12}{37}+\frac{1}{2}\right)\left(\frac{1}{3-\frac{1}{2}}-\frac{4}{7}\right)}$$

Fraction $\frac{-1}{6}$ can be rewritten as $-\frac{1}{6}$ by extracting the negative sign.

$$EF^{2}e^{2}ctuA=\frac{\frac{1}{2}\left(-\frac{1}{6}\right)\left(\frac{4}{7}+\frac{3}{10}\right)}{\left(\frac{12}{37}+\frac{1}{2}\right)\left(\frac{1}{3-\frac{1}{2}}-\frac{4}{7}\right)}$$

Multiply $\frac{1}{2}$ and $-\frac{1}{6}$ to get $-\frac{1}{12}$.

$$EF^{2}e^{2}ctuA=\frac{-\frac{1}{12}\left(\frac{4}{7}+\frac{3}{10}\right)}{\left(\frac{12}{37}+\frac{1}{2}\right)\left(\frac{1}{3-\frac{1}{2}}-\frac{4}{7}\right)}$$

Add $\frac{4}{7}$ and $\frac{3}{10}$ to get $\frac{61}{70}$.

$$EF^{2}e^{2}ctuA=\frac{-\frac{1}{12}\times \frac{61}{70}}{\left(\frac{12}{37}+\frac{1}{2}\right)\left(\frac{1}{3-\frac{1}{2}}-\frac{4}{7}\right)}$$

Multiply $-\frac{1}{12}$ and $\frac{61}{70}$ to get $-\frac{61}{840}$.

$$EF^{2}e^{2}ctuA=\frac{-\frac{61}{840}}{\left(\frac{12}{37}+\frac{1}{2}\right)\left(\frac{1}{3-\frac{1}{2}}-\frac{4}{7}\right)}$$

Add $\frac{12}{37}$ and $\frac{1}{2}$ to get $\frac{61}{74}$.

$$EF^{2}e^{2}ctuA=\frac{-\frac{61}{840}}{\frac{61}{74}\left(\frac{1}{3-\frac{1}{2}}-\frac{4}{7}\right)}$$

Subtract $\frac{1}{2}$ from $3$ to get $\frac{5}{2}$.

$$EF^{2}e^{2}ctuA=\frac{-\frac{61}{840}}{\frac{61}{74}\left(\frac{1}{\frac{5}{2}}-\frac{4}{7}\right)}$$

Divide $1$ by $\frac{5}{2}$ by multiplying $1$ by the reciprocal of $\frac{5}{2}$.

$$EF^{2}e^{2}ctuA=\frac{-\frac{61}{840}}{\frac{61}{74}\left(1\times \frac{2}{5}-\frac{4}{7}\right)}$$

Multiply $1$ and $\frac{2}{5}$ to get $\frac{2}{5}$.

$$EF^{2}e^{2}ctuA=\frac{-\frac{61}{840}}{\frac{61}{74}\left(\frac{2}{5}-\frac{4}{7}\right)}$$

Subtract $\frac{4}{7}$ from $\frac{2}{5}$ to get $-\frac{6}{35}$.

$$EF^{2}e^{2}ctuA=\frac{-\frac{61}{840}}{\frac{61}{74}\left(-\frac{6}{35}\right)}$$

Multiply $\frac{61}{74}$ and $-\frac{6}{35}$ to get $-\frac{183}{1295}$.

$$EF^{2}e^{2}ctuA=\frac{-\frac{61}{840}}{-\frac{183}{1295}}$$

Divide $-\frac{61}{840}$ by $-\frac{183}{1295}$ by multiplying $-\frac{61}{840}$ by the reciprocal of $-\frac{183}{1295}$.

$$EF^{2}e^{2}ctuA=-\frac{61}{840}\left(-\frac{1295}{183}\right)$$

Multiply $-\frac{61}{840}$ and $-\frac{1295}{183}$ to get $\frac{37}{72}$.

$$EF^{2}e^{2}ctuA=\frac{37}{72}$$

The equation is in standard form.

$$e^{2}EctuF^{2}A=\frac{37}{72}$$

Divide both sides by $EF^{2}e^{2}ctu$.

$$\frac{e^{2}EctuF^{2}A}{e^{2}EctuF^{2}}=\frac{\frac{37}{72}}{e^{2}EctuF^{2}}$$

Dividing by $EF^{2}e^{2}ctu$ undoes the multiplication by $EF^{2}e^{2}ctu$.

$$A=\frac{\frac{37}{72}}{e^{2}EctuF^{2}}$$

Divide $\frac{37}{72}$ by $EF^{2}e^{2}ctu$.

$$A=\frac{37}{72Ectu\left(eF\right)^{2}}$$

Solve for E

$E=\frac{37}{72Actu\left(eF\right)^{2}}$
$A\neq 0\text{ and }u\neq 0\text{ and }c\neq 0\text{ and }t\neq 0\text{ and }F\neq 0$

Steps for Solving Linear Equation

Multiply $F$ and $F$ to get $F^{2}$.

$$EF^{2}ectueA=\frac{\frac{\frac{1}{2}\times \frac{-1}{2+\frac{3}{3}+3}}{\frac{12}{37}+\frac{1}{2}}}{\frac{\frac{1}{3-\frac{1}{2}}-\frac{4}{7}}{\frac{4}{7}+\frac{3}{10}}}$$

Multiply $e$ and $e$ to get $e^{2}$.

$$EF^{2}e^{2}ctuA=\frac{\frac{\frac{1}{2}\times \frac{-1}{2+\frac{3}{3}+3}}{\frac{12}{37}+\frac{1}{2}}}{\frac{\frac{1}{3-\frac{1}{2}}-\frac{4}{7}}{\frac{4}{7}+\frac{3}{10}}}$$

Divide $\frac{\frac{1}{2}\times \frac{-1}{2+\frac{3}{3}+3}}{\frac{12}{37}+\frac{1}{2}}$ by $\frac{\frac{1}{3-\frac{1}{2}}-\frac{4}{7}}{\frac{4}{7}+\frac{3}{10}}$ by multiplying $\frac{\frac{1}{2}\times \frac{-1}{2+\frac{3}{3}+3}}{\frac{12}{37}+\frac{1}{2}}$ by the reciprocal of $\frac{\frac{1}{3-\frac{1}{2}}-\frac{4}{7}}{\frac{4}{7}+\frac{3}{10}}$.

$$EF^{2}e^{2}ctuA=\frac{\frac{1}{2}\times \frac{-1}{2+\frac{3}{3}+3}\left(\frac{4}{7}+\frac{3}{10}\right)}{\left(\frac{12}{37}+\frac{1}{2}\right)\left(\frac{1}{3-\frac{1}{2}}-\frac{4}{7}\right)}$$

Divide $3$ by $3$ to get $1$.

$$EF^{2}e^{2}ctuA=\frac{\frac{1}{2}\times \frac{-1}{2+1+3}\left(\frac{4}{7}+\frac{3}{10}\right)}{\left(\frac{12}{37}+\frac{1}{2}\right)\left(\frac{1}{3-\frac{1}{2}}-\frac{4}{7}\right)}$$

Add $2$ and $1$ to get $3$.

$$EF^{2}e^{2}ctuA=\frac{\frac{1}{2}\times \frac{-1}{3+3}\left(\frac{4}{7}+\frac{3}{10}\right)}{\left(\frac{12}{37}+\frac{1}{2}\right)\left(\frac{1}{3-\frac{1}{2}}-\frac{4}{7}\right)}$$

Add $3$ and $3$ to get $6$.

$$EF^{2}e^{2}ctuA=\frac{\frac{1}{2}\times \frac{-1}{6}\left(\frac{4}{7}+\frac{3}{10}\right)}{\left(\frac{12}{37}+\frac{1}{2}\right)\left(\frac{1}{3-\frac{1}{2}}-\frac{4}{7}\right)}$$

Fraction $\frac{-1}{6}$ can be rewritten as $-\frac{1}{6}$ by extracting the negative sign.

$$EF^{2}e^{2}ctuA=\frac{\frac{1}{2}\left(-\frac{1}{6}\right)\left(\frac{4}{7}+\frac{3}{10}\right)}{\left(\frac{12}{37}+\frac{1}{2}\right)\left(\frac{1}{3-\frac{1}{2}}-\frac{4}{7}\right)}$$

Multiply $\frac{1}{2}$ and $-\frac{1}{6}$ to get $-\frac{1}{12}$.

$$EF^{2}e^{2}ctuA=\frac{-\frac{1}{12}\left(\frac{4}{7}+\frac{3}{10}\right)}{\left(\frac{12}{37}+\frac{1}{2}\right)\left(\frac{1}{3-\frac{1}{2}}-\frac{4}{7}\right)}$$

Add $\frac{4}{7}$ and $\frac{3}{10}$ to get $\frac{61}{70}$.

$$EF^{2}e^{2}ctuA=\frac{-\frac{1}{12}\times \frac{61}{70}}{\left(\frac{12}{37}+\frac{1}{2}\right)\left(\frac{1}{3-\frac{1}{2}}-\frac{4}{7}\right)}$$

Multiply $-\frac{1}{12}$ and $\frac{61}{70}$ to get $-\frac{61}{840}$.

$$EF^{2}e^{2}ctuA=\frac{-\frac{61}{840}}{\left(\frac{12}{37}+\frac{1}{2}\right)\left(\frac{1}{3-\frac{1}{2}}-\frac{4}{7}\right)}$$

Add $\frac{12}{37}$ and $\frac{1}{2}$ to get $\frac{61}{74}$.

$$EF^{2}e^{2}ctuA=\frac{-\frac{61}{840}}{\frac{61}{74}\left(\frac{1}{3-\frac{1}{2}}-\frac{4}{7}\right)}$$

Subtract $\frac{1}{2}$ from $3$ to get $\frac{5}{2}$.

$$EF^{2}e^{2}ctuA=\frac{-\frac{61}{840}}{\frac{61}{74}\left(\frac{1}{\frac{5}{2}}-\frac{4}{7}\right)}$$

Divide $1$ by $\frac{5}{2}$ by multiplying $1$ by the reciprocal of $\frac{5}{2}$.

$$EF^{2}e^{2}ctuA=\frac{-\frac{61}{840}}{\frac{61}{74}\left(1\times \frac{2}{5}-\frac{4}{7}\right)}$$

Multiply $1$ and $\frac{2}{5}$ to get $\frac{2}{5}$.

$$EF^{2}e^{2}ctuA=\frac{-\frac{61}{840}}{\frac{61}{74}\left(\frac{2}{5}-\frac{4}{7}\right)}$$

Subtract $\frac{4}{7}$ from $\frac{2}{5}$ to get $-\frac{6}{35}$.

$$EF^{2}e^{2}ctuA=\frac{-\frac{61}{840}}{\frac{61}{74}\left(-\frac{6}{35}\right)}$$

Multiply $\frac{61}{74}$ and $-\frac{6}{35}$ to get $-\frac{183}{1295}$.

$$EF^{2}e^{2}ctuA=\frac{-\frac{61}{840}}{-\frac{183}{1295}}$$

Divide $-\frac{61}{840}$ by $-\frac{183}{1295}$ by multiplying $-\frac{61}{840}$ by the reciprocal of $-\frac{183}{1295}$.

$$EF^{2}e^{2}ctuA=-\frac{61}{840}\left(-\frac{1295}{183}\right)$$

Multiply $-\frac{61}{840}$ and $-\frac{1295}{183}$ to get $\frac{37}{72}$.

$$EF^{2}e^{2}ctuA=\frac{37}{72}$$

The equation is in standard form.

$$e^{2}ActuF^{2}E=\frac{37}{72}$$

Divide both sides by $F^{2}e^{2}ctuA$.

$$\frac{e^{2}ActuF^{2}E}{e^{2}ActuF^{2}}=\frac{\frac{37}{72}}{e^{2}ActuF^{2}}$$

Dividing by $F^{2}e^{2}ctuA$ undoes the multiplication by $F^{2}e^{2}ctuA$.

$$E=\frac{\frac{37}{72}}{e^{2}ActuF^{2}}$$

Divide $\frac{37}{72}$ by $F^{2}e^{2}ctuA$.

$$E=\frac{37}{72Actu\left(eF\right)^{2}}$$