Question

$$=12\frac{\sqrt{3}}{4}(fidy)^{2}+x\times b$$

Answer

$$x=(12*sqrt(34)*f^2*d^2*y^2)/b$$

Solution


Use Multiplication Distributive Property: \({(xy)}^{a}={x}^{a}{y}^{a}\).
\[=12\sqrt{34}{f}^{2}{\imath }^{2}{d}^{2}{y}^{2}+xb\]
Use Square Rule: \({i}^{2}=-1\).
\[=12\sqrt{34}{f}^{2}\times -1\times {d}^{2}{y}^{2}+xb\]
Subtract \(12\sqrt{34}{f}^{2}\times -1\times {d}^{2}{y}^{2}\) from both sides.
\[-12\sqrt{34}{f}^{2}\times -1\times {d}^{2}{y}^{2}=xb\]
Simplify  \(12\sqrt{34}{f}^{2}\times -1\times {d}^{2}{y}^{2}\)  to  \(-12{f}^{2}{d}^{2}{y}^{2}\sqrt{34}\).
\[-(-12{f}^{2}{d}^{2}{y}^{2}\sqrt{34})=xb\]
Regroup terms.
\[-(-12\sqrt{34}{f}^{2}{d}^{2}{y}^{2})=xb\]
Remove parentheses.
\[12\sqrt{34}{f}^{2}{d}^{2}{y}^{2}=xb\]
Divide both sides by \(b\).
\[\frac{12\sqrt{34}{f}^{2}{d}^{2}{y}^{2}}{b}=x\]
Switch sides.
\[x=\frac{12\sqrt{34}{f}^{2}{d}^{2}{y}^{2}}{b}\]