How to solve =16+3-5/2*4

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve =16+3-5/2*4 | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$=16+3-5\div2\times4$$

Evaluate

$9$

Solution Steps

Add $16$ and $3$ to get $19$.

$$19-\frac{5}{2}\times 4$$

Express $\frac{5}{2}\times 4$ as a single fraction.

$$19-\frac{5\times 4}{2}$$

Multiply $5$ and $4$ to get $20$.

$$19-\frac{20}{2}$$

Divide $20$ by $2$ to get $10$.

$$19-10$$

Subtract $10$ from $19$ to get $9$.

$$9$$

Show Solution

Factor

$3^{2}$

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