Solve 9x 4y ) ( y) =3x^ 3 -6x^ 2 +2; q(x) = 2x ^ 2 - 5 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$= 3 x ^ { 3 } - 6 x ^ { 2 } + 2 q ( x ) = 2 x ^ { 2 } - 5$$

Solve for q

$q=-\frac{3x^{2}}{2}+4x-\frac{5}{2x}$
$x\neq 0$

Steps for Solving Linear Equation

Subtract $3x^{3}$ from both sides.

$$-6x^{2}+2qx=2x^{2}-5-3x^{3}$$

Add $6x^{2}$ to both sides.

$$2qx=2x^{2}-5-3x^{3}+6x^{2}$$

Combine $2x^{2}$ and $6x^{2}$ to get $8x^{2}$.

$$2qx=8x^{2}-5-3x^{3}$$

The equation is in standard form.

$$2xq=-3x^{3}+8x^{2}-5$$

Divide both sides by $2x$.

$$\frac{2xq}{2x}=\frac{-3x^{3}+8x^{2}-5}{2x}$$

Dividing by $2x$ undoes the multiplication by $2x$.

$$q=\frac{-3x^{3}+8x^{2}-5}{2x}$$

Divide $8x^{2}-5-3x^{3}$ by $2x$.

$$q=-\frac{3x^{2}}{2}+4x-\frac{5}{2x}$$