How to solve 4 )=6( y+2 4 )+3

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 4 )=6( y+2 4 )+3 | Equatix

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Question

$$= 6 ( \frac { y + 2 } { 4 } ) + 3$$

Evaluate

$\frac{3\left(y+4\right)}{2}$

Short Solution Steps

Express $6\times \frac{y+2}{4}$ as a single fraction.

$$\frac{6\left(y+2\right)}{4}+3$$

To add or subtract expressions, expand them to make their denominators the same. Multiply $3$ times $\frac{4}{4}$.

$$\frac{6\left(y+2\right)}{4}+\frac{3\times 4}{4}$$

Since $\frac{6\left(y+2\right)}{4}$ and $\frac{3\times 4}{4}$ have the same denominator, add them by adding their numerators.

$$\frac{6\left(y+2\right)+3\times 4}{4}$$

Do the multiplications in $6\left(y+2\right)+3\times 4$.

$$\frac{6y+12+12}{4}$$

Combine like terms in $6y+12+12$.

$$\frac{6y+24}{4}$$

Show Solution

Expand

$\frac{3y}{2}+6$

Short Solution Steps

Express $6\times \frac{y+2}{4}$ as a single fraction.

$$\frac{6\left(y+2\right)}{4}+3$$

To add or subtract expressions, expand them to make their denominators the same. Multiply $3$ times $\frac{4}{4}$.

$$\frac{6\left(y+2\right)}{4}+\frac{3\times 4}{4}$$

Since $\frac{6\left(y+2\right)}{4}$ and $\frac{3\times 4}{4}$ have the same denominator, add them by adding their numerators.

$$\frac{6\left(y+2\right)+3\times 4}{4}$$

Do the multiplications in $6\left(y+2\right)+3\times 4$.

$$\frac{6y+12+12}{4}$$

Combine like terms in $6y+12+12$.

$$\frac{6y+24}{4}$$

Show Solution

Basic Math

Pre-Algebra

Algebra

Trigonometry

Calculus

Precalculus

Statistics

Finite Math

Linear Algebra

Chemistry

Example

Question

Evaluate

Short Solution Steps

Expand

Short Solution Steps