$$= \frac { 1 } { 2 + 15 + i }$$
$\frac{17}{290}-\frac{1}{290}i\approx 0.05862069-0.003448276i$
$$\frac{1}{2+15+i}$$
$$\frac{1}{17+i}$$
$$\frac{1\left(17-i\right)}{\left(17+i\right)\left(17-i\right)}$$
$$\frac{1\left(17-i\right)}{17^{2}-i^{2}}$$
$$\frac{1\left(17-i\right)}{290}$$
$$\frac{17-i}{290}$$
$$\frac{17}{290}-\frac{1}{290}i$$
Show Solution
Hide Solution
$\frac{17}{290} = 0.05862068965517241$
$$Re(\frac{1}{2+15+i})$$
$$Re(\frac{1}{17+i})$$
$$Re(\frac{1\left(17-i\right)}{\left(17+i\right)\left(17-i\right)})$$
$$Re(\frac{1\left(17-i\right)}{17^{2}-i^{2}})$$
$$Re(\frac{1\left(17-i\right)}{290})$$
$$Re(\frac{17-i}{290})$$
$$Re(\frac{17}{290}-\frac{1}{290}i)$$
$$\frac{17}{290}$$
