How to solve = 1 20 + 1 30

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve = 1 20 + 1 30 | Equatix

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$$=\frac{1}{20}+\frac{1}{30}$$

$\frac{1}{12}\approx 0.083333333$

Least common multiple of $20$ and $30$ is $60$. Convert $\frac{1}{20}$ and $\frac{1}{30}$ to fractions with denominator $60$.

$$\frac{3}{60}+\frac{2}{60}$$

Since $\frac{3}{60}$ and $\frac{2}{60}$ have the same denominator, add them by adding their numerators.

$$\frac{3+2}{60}$$

Add $3$ and $2$ to get $5$.

$$\frac{5}{60}$$

Reduce the fraction $\frac{5}{60}$ to lowest terms by extracting and canceling out $5$.

$$\frac{1}{12}$$

$\frac{1}{2 ^ {2} \cdot 3} = 0.08333333333333333$