How to solve = 1 5 - 1 5 * 7 2

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve = 1 5 - 1 5 * 7 2 | Equatix

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$$=\frac{1}{5}-\frac{1}{5}\times\frac{7}{2}$$

$-\frac{1}{2}=-0.5$

Multiply $\frac{1}{5}$ times $\frac{7}{2}$ by multiplying numerator times numerator and denominator times denominator.

$$\frac{1}{5}-\frac{1\times 7}{5\times 2}$$

Do the multiplications in the fraction $\frac{1\times 7}{5\times 2}$.

$$\frac{1}{5}-\frac{7}{10}$$

Least common multiple of $5$ and $10$ is $10$. Convert $\frac{1}{5}$ and $\frac{7}{10}$ to fractions with denominator $10$.

$$\frac{2}{10}-\frac{7}{10}$$

Since $\frac{2}{10}$ and $\frac{7}{10}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{2-7}{10}$$

Subtract $7$ from $2$ to get $-5$.

$$\frac{-5}{10}$$

Reduce the fraction $\frac{-5}{10}$ to lowest terms by extracting and canceling out $5$.

$$-\frac{1}{2}$$

$-\frac{1}{2} = -0.5$