How to solve = 5*4 7*4 = 20 28

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve = 5*4 7*4 = 20 28 | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

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$$=\frac{5\times4}{7\times4}=\frac{20}{28}$$

Verify

$\text{true}$

Solution Steps

Cancel out $4$ in both numerator and denominator.

$$\frac{5}{7}=\frac{20}{28}$$

Reduce the fraction $\frac{20}{28}$ to lowest terms by extracting and canceling out $4$.

$$\frac{5}{7}=\frac{5}{7}$$

Compare $\frac{5}{7}$ and $\frac{5}{7}$.

$$\text{true}$$

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