$$=\frac{\sqrt{3}}{4}x+2y+\frac{x}{3}+y$$
$\frac{3\sqrt{3}x+4x+36y}{12}$
$$\frac{3\sqrt{3}x+24y+4x+12y}{12}$$
Show Solution
Hide Solution
$\frac{\sqrt{3}x}{4}+\frac{x}{3}+3y$
