$$=\frac{x^{2}-2x-3}{x^{2}-9}\div\frac{x+3}{x^{2}-1}$$
$\left(\frac{x+1}{x+3}\right)^{2}\left(x-1\right)$
$$\frac{\left(x^{2}-2x-3\right)\left(x^{2}-1\right)}{\left(x^{2}-9\right)\left(x+3\right)}$$
$$\frac{\left(x-3\right)\left(x-1\right)\left(x+1\right)^{2}}{\left(x-3\right)\left(x+3\right)^{2}}$$
$$\frac{\left(x-1\right)\left(x+1\right)^{2}}{\left(x+3\right)^{2}}$$
$$\frac{x^{3}+x^{2}-x-1}{x^{2}+6x+9}$$
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$\frac{x^{3}+x^{2}-x-1}{\left(x+3\right)^{2}}$