Question

$$=lim\frac{x^{3}+7x^{2}-8x}{x\rightarrow4\ 3x^{2}-3}$$

Answer

$$l=-(IM*(-7*x^2+344*x^4+3))/(m*x^3)$$

Solution


Take out the constants.
\[=l\imath m{x}^{3}+7{x}^{2}-(8\times 43)xx{x}^{2}-3\]
Simplify  \(8\times 43\)  to  \(344\).
\[=l\imath m{x}^{3}+7{x}^{2}-344xx{x}^{2}-3\]
Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[=l\imath m{x}^{3}+7{x}^{2}-344{x}^{1+1+2}-3\]
Simplify  \(1+1\)  to  \(2\).
\[=l\imath m{x}^{3}+7{x}^{2}-344{x}^{2+2}-3\]
Simplify  \(2+2\)  to  \(4\).
\[=l\imath m{x}^{3}+7{x}^{2}-344{x}^{4}-3\]
Subtract \(7{x}^{2}\) from both sides.
\[-7{x}^{2}=l\imath m{x}^{3}-344{x}^{4}-3\]
Regroup terms.
\[-7{x}^{2}=\imath lm{x}^{3}-344{x}^{4}-3\]
Add \(344{x}^{4}\) to both sides.
\[-7{x}^{2}+344{x}^{4}=\imath lm{x}^{3}-3\]
Regroup terms.
\[-7{x}^{2}+344{x}^{4}=-3+\imath lm{x}^{3}\]
Add \(3\) to both sides.
\[-7{x}^{2}+344{x}^{4}+3=\imath lm{x}^{3}\]
Divide both sides by \(\imath \).
\[\frac{-7{x}^{2}+344{x}^{4}+3}{\imath }=lm{x}^{3}\]
Rationalize the denominator: \(\frac{-7{x}^{2}+344{x}^{4}+3}{\imath } \cdot \frac{\imath }{\imath }=-(-7{x}^{2}+344{x}^{4}+3)\imath \).
\[-(-7{x}^{2}+344{x}^{4}+3)\imath =lm{x}^{3}\]
Regroup terms.
\[-\imath (-7{x}^{2}+344{x}^{4}+3)=lm{x}^{3}\]
Divide both sides by \(m\).
\[-\frac{\imath (-7{x}^{2}+344{x}^{4}+3)}{m}=l{x}^{3}\]
Divide both sides by \({x}^{3}\).
\[-\frac{\frac{\imath (-7{x}^{2}+344{x}^{4}+3)}{m}}{{x}^{3}}=l\]
Simplify  \(\frac{\frac{\imath (-7{x}^{2}+344{x}^{4}+3)}{m}}{{x}^{3}}\)  to  \(\frac{\imath (-7{x}^{2}+344{x}^{4}+3)}{m{x}^{3}}\).
\[-\frac{\imath (-7{x}^{2}+344{x}^{4}+3)}{m{x}^{3}}=l\]
Switch sides.
\[l=-\frac{\imath (-7{x}^{2}+344{x}^{4}+3)}{m{x}^{3}}\]