Question

$$= \operatorname { A n t i l o g } [ \frac { 2 \times 1.10 } { 0.059 } ] =$$

Answer

$$An*log(0.059^2.2)*IM*x*t$$

Solution


Simplify.
\[2.2xtAn\imath \log{0.059}\]
Use Power Rule: \(\log_{b}{{x}^{c}}=c\log_{b}{x}\).
\[xtAn\imath \log{{0.059}^{2.2}}\]
Regroup terms.
\[An\log{{0.059}^{2.2}}\imath xt\]