$$=(2-3i)(1+i)^{2}-(2-i)^{3}$$
$4+15i$
$$\left(2-3i\right)\times \left(2i\right)-\left(2-i\right)^{3}$$
$$6+4i-\left(2-i\right)^{3}$$
$$6+4i-\left(2-11i\right)$$
$$4+15i$$
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$4$
$$Re(\left(2-3i\right)\times \left(2i\right)-\left(2-i\right)^{3})$$
$$Re(6+4i-\left(2-i\right)^{3})$$
$$Re(6+4i-\left(2-11i\right))$$
$$Re(4+15i)$$
$$4$$
